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5s^2-13s-36=0
a = 5; b = -13; c = -36;
Δ = b2-4ac
Δ = -132-4·5·(-36)
Δ = 889
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{889}}{2*5}=\frac{13-\sqrt{889}}{10} $$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{889}}{2*5}=\frac{13+\sqrt{889}}{10} $
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